binomial question

The value of the expression
Co2+C12+C22+...+Cn2 is

(a)22n-1

(b)2n(2nCn)

(c)2nCn

(d)None of these

2 Answers

6
nix_13 12 ·

nebody????

106
Asish Mahapatra ·

(1+x)n = C0 + C1x + C2x2 + ... + Cnxn
(x+1)n = C0xn + C1xn-1 + ... + C0

Multiplying both and equating the powers of xn
we get S = coefficient of xn in (1+x)2n
= 2nCn

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