1yaaa carry on delete.....
2 justify ur ans can d abv example b given?
Statement 1: If z1 and z2 are two complex numbers such that their product is a real number, then they are conjugate to each other
and
Statement 2: (x + iy) (x - iy) = x2 + y2, x, y R.
1.
Statement 1 is True, statement 2 is True; statement 2 is a correct explanation for statement 1.
2.
Statement 1 is True, statement 2 is True; statement 2 is not a correct explanation for statement 1.
3.
Statement 1 is True, statement 2 is False.
4.
Statement 1 is False, statement 2 is True.
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19 Answers
11@raghav... dont limit urself lyk dat... v can even dis-prove first statement wid d example given by gsns... always keep in mind dat a real no. is also a complex no. ... avoiding it may mislead u in problems dat u come across later...
1yes... it can be written as 1+0i...
Every real no. can be expressed as a complex no. in d above format... :)
1bt, though ur ex is complexno(havin real no as its subset)still u call them as real no... I think 4 usin complex no. in these typ f q, takin b≠0 in a+ib
1@gsns...
yeah, ur example is also valid to disprove statement 1... v need to recall dat real no.s are a subset of complex no.s... :)
1It is.... both 3i and -4i r complex no... and their prod is real...(so 1st stmt bcomes rong)
1ohhh yaaa gt it......can ma abv example b valid 4 d explanation??
1well, d ans is (4)...
explanation : product of two imaginary no.s is always a real no. ::: eg: (3i).(-4i) = 12
hope it's clear... :)
1hey can dis example b given.....
Z1=1+0i
Z2=1+0i
and hence product is a real no.??
1hey sry i just made a guess......i m also nt sure
den wats d ans??
1its obvious 4rm d statement naaaa
product f 2 complex no.s can b a real onli if der r conjugate 2 each othr naaa.......
well i thnk der is no othr example such dat product f 2 no,z iz real