Let f(n) be the least number of times you have to hit the key in the calculator to get a number less than 2 starting from n, n being a natural number. e.g. f(2) =1and f(5) =2. For how many natural numbers m such that 1<m<2008, is f(m) odd.
(bhatt sir stay away )
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2 Answers
624, 5 and numbers from
16, 17..... 255
'
hence 242 numbers
I hope what i am doing is correct.. otherwise.. the answer will not change even if the question was for 1<m<20008 (one more zero )
