24Dude since it is divisible by x2+x+1 then
h(ω)=h(ω2)=0
If f(x) and g(x) are 2 polynomials such that polynomial h(x)=xf(x^3)+x^2g(x^6)
is divisble by x^2+x+1
then find relation between f(1) and g(1)
i got the answer f(1)=-g(1)
but answer given is f(1)=±g(1)
plz help
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3 Answers
1h(x)=xf(x^3) +x^2g(x^6)
putting x=0
we get
h(0)=0
now
let h(x)=k(x^2 + x + 1)
now putting x=0
we get
k=0
so
h(x)=0 for any value of x
now
putting value of h(x) in original eqn
we get
xf(x^3) + x^2g(x^6)=0
putting x=1
we get
f(1)=-g(1)
dude i am also getting the same answer as urs...
but i think that we are both making mistakes in the x^2 part.....