Compleksh for u

If the complex sequence of numbers z0, z1, z2........satisfy z_0=i+\frac{1}{137} and for n≥1 z_{n+1}=\frac{z_n+i}{z_n-i}

then find the value of z2007

2 Answers

341
Hari Shankar ·

Let z_n = ix_n

Then the sequence satisfies x_{n+1} = \frac{x_n+1}{x_n-1} which is easy to see satisfies x_{n+2} = x_n

From this it is easy to see that z2007=z1 which can be easily computed

1
Che ·

:)

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