if you want a better method ,
put z=x+iy
then equate the part in imaginary =0
find y
and y2>0
but you still have to write
a=(1/2)(a+acon)+(a-acon))
put a-acon=Ai and similary for others
iif d roots of d equation z^2+az+b=0 are imaginary then find d condition on a ,acon ,b,b con
tell me d way 2 saolve such q's
plez b quick :'(
if you want a better method ,
put z=x+iy
then equate the part in imaginary =0
find y
and y2>0
but you still have to write
a=(1/2)(a+acon)+(a-acon))
put a-acon=Ai and similary for others
not that one ..
as the whole expression is 0 ,its imaginary part will also be equal to 0
okies,..........
bt can i do nething like since d roots r imaginary d product will b real and d sum imaginary ..............so taht quad ..sum and product of roots ........can i use this .........2 get d sol?
they hav said that d roots r imagnary .......
wat u ahv considerd may nt be so andsewr can b zero in this case
can u plez post d whole solution m nt gettin wat u r sayin ........
sorry
for roots of an eqn sum of roots can never be imaginary..........