Let a be a complex number,
ia3+a2-a+i = 0
then find maximum value of |a-3-4i|
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3 Answers
106see..
ia3+a2-a+i = 0
==>ia3+a2+i2a+i = 0
==> a2(ia+1) + i(ia+1) =0
==> (a2+i)(ia+1)=0
==> a = i or a = (-i)1/2
==> a=i,±(1/√2 - i/√2)
Now for a=i reqd valu=3√2
for a=1/√2 - i/√2, reqd valu = √26 + √2
for a= -(1/√2 - i/√2) reqd valu = √26 - √2
So, answr is √26 + √2
62ia3+a2-a+i = 0
ia(a2+i) +a2+i = 0
(1+ia)(a2+i) = 0
we know the 3 values of a
for each value of a find the value of the expression you have given!