complex num.

are you sure abt the problem , you see we get

(z²+1)(z²+1)≥1 = >(z²+1)((z)²+1)≥1 from the second condition

implying

|z|⁴+(z)²+z²+1≥1

let z= x+iy
which gives

|z|⁴+x²-y²+2xyi+x²-y²-2xyi≥0

giving

|z|⁴+2(x²-y²)≥0 --- (i)

now see that x=y and x=-y are both tangetns to the circle dexcribed in first equation ..

if the first equation doesnt satisfy then z has to be inside the circle .

but see that then we will have |x|>|y| in that region hence x²>y² and hence the inequality in (i) will be satisfied .. so one or the other must be true