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Lokesh Verma
·2009-02-12 04:23:17
Q 1 was solved sometime back on the forum.. I think it was given by eureka.. i will have to check..
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Lokesh Verma
·2009-02-12 04:26:10
http://targetiit.com/iit_jee_forum/posts/complex_geometry_295.html
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Hari Shankar
·2009-02-12 05:49:13
Q 1.
z lies on a circle for which the line joining (1,0) and (-1,0) are the ends of a diameter.
That means arg(1+z/1-z) = ±π/2.
Hence the argument of the square root of the number is ± π/4. Thus, the numbers lie on one of two perpendicular lines.
Q 2. Needs to be rephrased I guess. It should be: there exists a pair such that the angle between them is greater than or equal to 2Ï€/3.
Please check
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Lokesh Verma
·2009-02-12 06:09:33
this proof for the first part is awesome :)
I wonder how much I have to learn to equal prophet :)
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Lokesh Verma
·2009-02-12 06:09:48
but then this was doable ;)
1
mkagenius
·2009-02-12 06:53:00
BHAIYA HOW TO APPROACH GRAPHICALLY....
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Lokesh Verma
·2009-02-12 06:55:02
Rotation as done by Prophet is a graphical method if u understand it well enuf :)