(1+w)n=(1+w2)n
now put n=1 it fails
put n=2
i will get 1+w2+2w≠1+w+2w2
it also fails
put n=3
1+1+3w2+3w=1+1+3w2+3w
which is always true
so the answer is 3 [1]
it is also intutive as w is a cube root of unity[4]
the least positive value of "n" for which (1+w2)n = (1+w4)n, where w is a non real cube root of unity is .......... ?
(1+w)n=(1+w2)n
now put n=1 it fails
put n=2
i will get 1+w2+2w≠1+w+2w2
it also fails
put n=3
1+1+3w2+3w=1+1+3w2+3w
which is always true
so the answer is 3 [1]
it is also intutive as w is a cube root of unity[4]