39what is the question dude? if n=1 u get 12 which is not divisible by 6!.
PT. 22n*3nis divsible by (6n)!.can anyone do dis by using logic . i mean to say dat can we do dis widout using pen and paper.Nishant bhaiya i thnk u got wat i wantd to say....
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39
6no actually i have an book given by aakash tutorials..nw dis question has been solved by some of their logic...bt i felt hw is it possible..i'lllatr put up their soln.
39how can anyone provide a solution if the question is wrong...
how are u even agreeing with it??
cant u yourself see by putting values for `n` ???
62are u sure this is the question kalyan.. because as bhargav pointed out the question is wrong even for n=1
6the sum is...is (6n)! divisible by 22n*3n.i made a mistake in typing..can ny1 tell me nw..nw the sum is also correct??if we put n=1,it is divisible.
62oh you have reversed the question from a is divisible by b to b is divisible by a :P
You need to either use induction or otherwise prove that the higest power of 2 in (6n)! is greater than 2n and 3 is n
Proving 3^n is simple ... can you think this out?
6ohhhkkk.. i think i have got it...
(6n)!=(6n-1)*(6n-2)*(6n-3)....3*2*1.
from every 2nd term we get 2 common n every third we get 3 common..can we use this logic to prove the sum??