11WE can take 3x67 common from both terms, which is equal to 201. So, the remainder is 0
Find the remainder when [(2 × 4 × 6 × 8 × 10 ×…× 200) – (1 × 3 × 5 × 7 × 9 ×…× 199)] is divided by 201.
do not take more than 2 min.....
-
UP 0 DOWN 0 0 5
5 Answers
11
1If p be the first of n arithmetic means between two numbers,
and q the first of n harmonic means between the same two numbers,
prove that the value of q cannot lie between p and {((n+1)/(n-1))^2}p
1@johncena ur 2nd Q isnt clear. hw can there be n arithmetic means bet. 2 nubers??
is it "p is the arithmetic mean of first n natural no.s"
1if a1,a2,a3,......,an are n arithmetic means between a and b, then
a,a1,a2,a3,..........,b are in AP.