what is the shortest method to find the values of -
(a)Co/2-C1/3+C2/4-C3/5...upto (n+1) terms.
(b)C1/2+C2/4+C3/6+...
ans of (a) 1/(n+1)(n+2)
ans of (b) 2n-1/n+1
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1 Answers
1061. Consider the equation
(1-x)n+1 = C0 - C1x + C2x2 - ...+Cn+1xn+1
multiply by x throughout and integrate wrt x and then put x=1
2. Consider: i am assuming to n terms
(1+x)n = C0 + C1x + C2x2+ ...+Cnxn
Divide both sides by x and then integrate. and then put x=1
U wud get the value for C1+C2/2+C3/3+...
multiply the value by 1/2 and u will get the answer
