if x is real then prove that the expression
(x2-2xcos2θ+1)/(x2-2xcos2φ+1)
lies btween sin2θ/sin2φ and cos2θ/cos2φ.
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1 Answers
Manish Shankar
·2009-08-07 22:17:56
Let (x2-2xcos2θ+1)/(x2-2xcos2φ+1)=m
then
(x2-2xcos2θ+1)=m(x2-2xcos2φ+1)
or x2-2x{mcos2φ-cos2θ}/(m-1) +1=0
put discriminant≥0 and you will get what you want