if 1>=a>=b>=c>=0 & λ is a real root of the equation x3+ax2+bx+c =0 then max. value of modulus λ is ?
a)1
b)1.5
c)2
d)0.5
1since the maximum value of lambda will be when a=b=c=1
then the equation becomes x3+x2+x+1=0
and the root lambda is =-1 hence |lambda| =|-1|= 1
hence option a
11@ amit
i think this could be wrong[2]
if i am wrong justify ur STATEMENT 1
kamal
α+β+γ=-a
αβ+βγ+αγ=b
αβγ=-c
then u have to slve these three simultaneously using the give n condition
if u rnt able to solve it baad mein phir pooch lena
but that was a clue[1]
11kamal do u agree with the way amit proceeded [7][7][7]
or the way i told u
i didnt found the answer
i just gave u a hint
1if lambda is a root..... then substitue for it in the given eqn
for extrema diff the eqn wrt lambda
solve for lambda..... its a quadratic...
but after that i dunno how to proceed
