equation

if 1>=a>=b>=c>=0 & λ is a real root of the equation x3+ax2+bx+c =0 then max. value of modulus λ is ?
a)1
b)1.5
c)2
d)0.5

8 Answers

1
Optimus Prime ·

since the maximum value of lambda will be when a=b=c=1

then the equation becomes x3+x2+x+1=0

and the root lambda is =-1 hence |lambda| =|-1|= 1

hence option a

11
Mani Pal Singh ·

@ amit
i think this could be wrong[2]
if i am wrong justify ur STATEMENT 1

kamal

α+β+γ=-a
αβ+βγ+αγ=b
αβγ=-c

then u have to slve these three simultaneously using the give n condition
if u rnt able to solve it baad mein phir pooch lena
but that was a clue[1]

1
kamalendu ghosh ·

well the answer is 1

11
Mani Pal Singh ·

kamal do u agree with the way amit proceeded [7][7][7]
or the way i told u
i didnt found the answer
i just gave u a hint

1
kamalendu ghosh ·

@manipal
yeh sab to mujhe bhi pata hain....par inse nahin hua

11
Mani Pal Singh ·

k then i will try!!!!!!!!!!!

1
iitjeeaspirant19 kashyap ·

hey.... how to type eqns????????

1
iitjeeaspirant19 kashyap ·

if lambda is a root..... then substitue for it in the given eqn
for extrema diff the eqn wrt lambda
solve for lambda..... its a quadratic...

but after that i dunno how to proceed

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