Anyone?
If α,β,γ are cube roots of p (p<0) then for any x,y,z evaluate:
(xα+yβ+zγ)/(xβ+yγ+zα)
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5 Answers
Lokesh Verma
·2009-01-05 20:14:49
(xα+yβ+zγ)/(xβ+yγ+zα)
=1/α.α(xα+yβ+zγ)/(xβ+yγ+zα)
= 1/α . (xα.α+yβ.α+zγ.α)/(xβ+yγ+zα)
= 1/α . (xβ+yγ+zα)/(xβ+yγ+zα)
= 1/α