2) b2-4ac≥0
for b=1 a=c=0 satisfy
for b=2 a=c=1
forb=3 (1,1),(1,2),(2,1)
for b=4 (1,1)....(1,4)
(2,1),(2,2)
(3,1) ,(4,1)
for b=5 (1,1).....(1,6)
(2,1).,....(2,3)
(3,1)(3,2)(4,1)(5,1)(6,1)
for b=6 (1,1)......(1,6)
(2,1)...(2,4)
(3,1)...(3,3)
(4,1)(4,2)(5,1)(6,1)
=>favourable=43
P=43/216
any other shorter method is welocme