1
voldy
·2009-01-08 05:59:51
guys believe me , this is an NMO standard problem . I think , never asked in JEE. only Nishant and Priyam , prophet and other math geeks can solve. :)
24
eureka123
·2009-01-08 06:05:22
Yes it is difficult but not impossible........and do u know level of mathematics paper is taking huge leaps year after year......I wont be surprised if in a couple of years Olympiad level mathematics paper comes(We may see a trailer of that in 2009)......So we should be prepared for WORST...........
I hope U r not angry with me........I just wanted to say that on seeing tough problems we shouldnt run away....There is no prophet on earth.....Its just humans.....
11
Anirudh Narayanan
·2009-01-08 06:49:24
i don't expect myself to solve this problem. So expectation of me finding the person's expectation is 0. [2]
Btw when the math lords solve this question, I request them to post the full solution along with their thought process. Please guys [1]
62
Lokesh Verma
·2009-01-08 07:05:40
I think it should be m/2
This is my gut feeling :)
See the justification si that every coin has equal probability to be picked before and after the coin with denomination M.
So expected value is m/2
62
Lokesh Verma
·2009-01-08 07:06:06
btw it was amusing to see urself painted "geek" :D :P
62
Lokesh Verma
·2009-01-08 11:29:05
yeah eureka.. it is the same.. (almost)
you are counting the expected value just after the coin was picked..
i am counting just before :)