1! + 2! + 3! ............. + n! = k! where kεI+
find all solutions
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1 Answers
Lokesh Verma
·2009-05-18 22:40:30
clearly, k>n
lets see
1! + 2! + 3! ............. + n! ...
each term is <=n!
so the sum of these is <n. n! < (n+1)!
Thus there will be no solution except when n=1