Faraday question

If high voltage (440V) current is applied on the field which is given by the graph y-mod(y)-x+mod(x)=0.Then on which of the following curve Mr.Faraday can move so that he remains safe.

a)y=e-mod(X) b)y=1/x
c)y=signum(x) d)y=-mod (m+mod(x)) (m >3)

11 Answers

11
Anirudh Narayanan ·

y-lyl=x-lxl

in I quad,

y-y=x-x
0=0?????
[12]The whole of I quad satisfies this.[7]

In II Quad,
y-y=x+x

x=0

[12] only +y axis

In III Quad,
y=x

In IV Quad,
y=0

[7][7][7][7][7][7][7][7][7][7]

3
msp ·

but the answer is d machan

11
Anirudh Narayanan ·

No da. Dir of elec field itself is not clear [2]

3
msp ·

machan ithu vandhu oru physics question illa ithu oru maths testpaperla irundhu eduthen

62
Lokesh Verma ·

y-mod(y)-x+mod(x)=0

so y+|y|=x+|x|

if x>0, y>0

then it is x=y

when x<=0, y>=0, then y=0
when x>=0, y<=0, then x=0

when x<0, y<0, then any point axis...

The option d is the only one which goes with the one given above and is equipotential .. bcos the line parallel to the x axis and in the 4th quadrant will be equipotential

11
Anirudh Narayanan ·

Bhaiyyah, isn't it
y-lyl=x-lxl?

1
Pavithra Ramamoorthy ·

ani.. see q properly...

1
Akshay Pamnani ·

Wrong question,question is on which of the curves can Mr Calculus move to remain safe

62
Lokesh Verma ·

yup i did x+|x| ramkumar and ani..

I dont know why.. but i am getting none of these! :(

11
Anirudh Narayanan ·

I din undrstnd why it is y+lyl=x+lxl

1
Akshay Pamnani ·

None OF These

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