Thanks :)
COMPREHENTION
There is a point 'p' inside an equilateral triangle ABC of side d whose distance from the vertices is 3,4,5 . Rotate the triangle, through 60° about C . Let A go to A' and P to P'.
1) The area of triangle PAP' is
(A) 8 (B) 12 (C) 6 (D) none of these
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UP 0 DOWN 0 0 8
8 Answers
after reading ur ques .....i realized it had traces of a ques i read loong time back...
though not exactly same......
these links will be useful...atelast 6 diff type of solns have been given.
http://mathcentral.uregina.ca/mp/previous2008/dec08sol.php
http://mathforum.org/library/drmath/view/61863.html
i am assuming uttara meant 3,4,5,respectively
the solution becomes easy from geometry
@Akari I dint get ur figure
Can u plzzz label it
& ya i did mean " 3,4,5,respectively " PA = 3 PB = 4 PC = 5
But in ur fig I cant make out which r A B C
So plzzzzzzzzz label it
or anyone else who understood the fig can label it plzzzzzzz