find a

Find the values of ‘a’ for which the expression x2 – (3a – 1)x + 2a2 + 2a – 11 is always positve.

2 Answers

1
Anirudh Kumar ·

this is simply D< 0

(3a-1)2- 4 (2a2+2a-11)< 0

rhis is simple

21
omkar ·

x2 – (3a – 1) x + 2a2 + 2a – 11 > 0

D < 0

(3a – 1)2 – 4 (2a2 + 2a –11) < 0

9a2 – 6a + 1 – 8a2 – 8a + 44 < 0

a2 – 14a + 45 < 0

(a – 9) (a – 5) < 0

5 < a < 9

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