1 Answers
Tush Watts
·2009-09-24 18:04:49
Ans) We know that
cos z = (e - iz + e iz ) / 2
= [e i2 log (2-√3) + e - i 2 log (2 -√3) ] / 1
= [ e log (2-√3) -1 + e log (2-√3) ] / 2
=[ (2-√3) + (2-√3) -1 ] / 2
=2