f(x)f(y)-[f(x/y)+f(xy)]/2 = cos(logx)cos(logy)-[cos(logx-logy)+cos(logx+logy)]
now take logx=A and logy=B and solve
i thimk answer is 0
- Swarna Kamal Dhyawala *thinkUpvote·0· Reply ·2013-04-22 05:15:52
How do I solve this:
f(x)=cos(logx)
find f(x)f(y)-[f(x/y)+f(xy)]/2
Hint:
Use the properties of logarithms here to evaluate [f(x/y) + f(xy)]....and then you can solve the rest.
f(x)f(y)-[f(x/y)+f(xy)]/2 = cos(logx)cos(logy)-[cos(logx-logy)+cos(logx+logy)]
now take logx=A and logy=B and solve
i thimk answer is 0
Yes even I got the answer as 0 :)