1If " 2 " is subtracted from each root , then the eqn . having those two roots is -
( x - 2 ) 2 + b ( x - 2 ) + c = 0
or , x 2 + x ( b - 4 ) + c + 4 - 2 b = 0
The roots of the eqn. having the roots which are reciprocals to that of the given roots is -
b x 2 + c x + 1 = 0
By comparingthe sum of the roots and the product of the roots ,
b - 4 = - cb
c + 4 - 2 b = 1b
Now you can solve for " b " and " c " .
