1wen
x (0,ln (3/2)).............2≤3e-x<3.......... so [3e-x] is 2
x (ln(3/2),ln 3).............1≤3e-x<2 ....... so [3e-x] is 1
x (ln3,∞).............0<3e-x<1....... so [3e-x] is 0
Q1. Let f(x) = ax^4+bx^3+cx^2+dx+e where
a,b,c,d,e\; \; \epsilon \; R
, a≠0, b2>8ac/3 and g(x) = lf(lxl)l
, then maximum possible no. of points at which g(x) is non-differentiable is _______
Q2.\int_{0}^{\infty }{\left[3e^{-x} \right]}dx = lnk
Then [k] is _____
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7 Answers
1
1first one , answer is 9 ?
consider this simple 4 th degree equation
P(x)=(x-1)(x-2)(x-3)(x-4)
now graph of |P(|x|)| will be
clearly u can see points wer the graph is getting sharp are
1,-1,2,-2,3,-3,4,-4,and 0
the graph is very easy to plot, took it from a software for better quality
is the graph vsisble
106akari.. a condition is given for Q1. i.e. b2 > 8ac/3.
using that i get that f''(x) > 0 for all x.
so i think ans should be 5...
@che: yeah even i got 9/2 but i dunno how the answer is given as 27/4
49oye akari the graph is not only visible but indeed it is imaginable...w really have to use our imagination to see it....[3][3][3][3][3]
abbe kuch nahi dikh raha hai....
bt still u have a software to draw beautiful graphs???
can u post the link to the free download of the software????
i am in bad need for it...
due to my lappy in whch paint works horribly without a mouse using thumb pad, i can never post good graphs...so indeed i have stopped posting the graphs...
please post the link please..[1][1][1][1][1]
1for 1st k=9/2 is correct
for any generalized n
\int_{0}^{\infty }{\left[ne^{-x} \right]}dx=log\left(\frac{n^{n}}{n!} \right)