yes i have got the ans = 2pi.
bcz It is a objective question..
with 4 ans and 2pi is one of them.
so can u show ur procedure.........
find sum of max. and min. value of sin-1(2x) +cos-1(2x)+sex-1(2x)
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UP 0 DOWN 0 0 3
3 Answers
man111 singh
·2010-05-15 08:04:38
Ricky
·2010-05-15 08:09:01
Max . value of sin - 1 2x + cos - 1 2x = pi / 2 , only when , - 1 / 2 ≤ x ≤ 1 / 2.
Again , when x = - 1 / 2 ,
sec - 1 2x = pi
Hence , max . value of the whole thing - 3 p i / 2
Similarly for x = 1 / 2 , the min value is -- p i / 2 as then sec - 1 2x = 0 .
Hence , ans -- 2 pi