36the question is different.....
u dont have log b / log a inside the bracket in the numerator...
[log {(log a)/(log b)} x (log b) / (log a)] / log {(log b)/(log a)}
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8 Answers
21assuming the q is correct
log((log alog b)(log blog a)) = log1 = 0
0/something nonzero = 0
3636mentioned that in my second post....
its like...
log of log a upon log b
upon
log of log b upon log a
nd the whole multiplied by
log b upon log a
bhavnao ko samjho.... :p