logarithm

assuming the q is correct

log((log alog b)(log blog a)) = log1 = 0

0/something nonzero = 0

the question is different.....
u dont have log b / log a inside the bracket in the numerator...

mentioned that in my second post....
its like...
log of log a upon log b
upon
log of log b upon log a
nd the whole multiplied by
log b upon log a
bhavnao ko samjho.... :p

''bhavnao ko samjho ''

nishant sir's dialouge ? :P

is it so?
most widely used dialogue
in my hostel.... :p

i hav first read this from his keyboard ;)

its - log b with the base a