And the answer is 12...
If three positive real numbers a, b, c are in A.P. and abc = 4 then minimum possible value of b is
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3 Answers
souvik seal
·2010-06-15 02:40:09
(b-d)b(b+d)=4
→b3-bd2=4
→b3=4+bd2
b is least when 4+bd2 is least
as all are +ve
least bd2 is 0
hence least value of b= 4^(1/3)
..........HEY d is common difference