Minimum value of f(x)

$\textbf{Find Minimum value of $\mathbf{f(x)=\left(\sqrt{-x^2+4x+21}-\sqrt{-x^2+3x+10}\right)}}$\\\\ Ans:\Rightarrow ::::=\sqrt{2}

3 Answers

62
Lokesh Verma ·

From the graph of the situation, the answer has to be -ve...

are u sure that root 2 is the correct answr?

1708
man111 singh ·

Yes Sir at x = 1 / 3

62
Lokesh Verma ·

yup now i realize why i had made that mistake...

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