Modulus

If z=i^{i^i.....âˆž}=A+iB then find lzl

7 Answers

z=i^z

so mod (z)=[mod(i)]^z

341

Hari Shankar ·2009-09-17 23:57:23

|z| by definition is a real number

sankara..

if the exponent is not a real number you cannot take modulus

okie sir.

z=a+ib

z=i^z = (e^{i pi/2})^a+ib

z=e^{i pi/2 x (a+ib)}

z=e^{i api/2 - bpi/2}

Now can you finish the rest?

a pink from my side for that :)

thanks bhargav... :)

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