hey sir u have posted the same answer twice!!!!!!!!!
4 Answers
Lokesh Verma
·2009-01-27 20:23:35
P(A/B) = P(A∩B)/P(B)
P(A/B).P(B) = P(A∩B) =P(A)+P(B)-P(AUB)
we know that P(AUB)<=1
hence part 1.
Lokesh Verma
·2009-01-27 20:24:10
P(A/B) = P(A∩B)/P(B)
P(A/B).P(B) = P(A∩B) =P(A)+P(B)-P(AUB)
we know that P(AUB)<=1
hence part 1.