the divisors are of the form 6 x (an odd number).
25200=2432527
after choosing a six we are left with 1power of 3, 2 of 5 and 1 of 7.
therfore total factors of the given form is 12.
- man111 singh Thanks KetanUpvote·0· Reply ·2013-02-24 04:25:10
\hspace{-16}$The no. of divisers of the form $\bf{12\lambda+6(\lambda\in \mathbb{N})}$ of the no. $\bf{25200}$
the divisors are of the form 6 x (an odd number).
25200=2432527
after choosing a six we are left with 1power of 3, 2 of 5 and 1 of 7.
therfore total factors of the given form is 12.