Number of solutions

so is the answer infinte solutions..........m not sure at all ...by the way wats the answer/?

Ans....only 1 solution (4.3, 0, 2.2)

I rmmbr this as a problem by Titu

Add up all three and get x+y+z=13.

Subtract the first eqn from the above to obtain

[x] +{z} = 10.7

From this can you argue that [x] = 10 and {z} = 0.7?

And also complete the problem?

Ans:- \left\{x \right\}+y +\left[z \right]=2.3 .........(1) \left[y \right]+\left\{z \right\}+x=4.5 ..........(2) \left\{y \right\}+\left[x \right]+z=6.2 ..........(3) add (1) and (2) and (3) we get x+y+z+(\left[x \right]+\left\{x \right\})+(\left[y \right]+\left\{y \right\})+(\left[z \right]+\left\{z \right\})= 2.3+4.5+6.2 and we now that \left[x \right]+\left\{x \right\}=x similarly for y and z we get 2(x+y+z)=13 (x+y+z)=6.5 ........(4) subtract (1) from (4)
(x-\left\{x \right\})+(z-\left[z \right])=6.5-2.3
\left[x \right]+\left\{z \right\}=4.2 or \left[x \right]=4 and \left\{z \right\}=0.2

means Integer part of x is equal to 4 and fractional part of z =0.2
similarly sub (2) from (4) we get
and similarly sub (2) from (4) we get \left\{x \right\}+\left[z \right]=2.0 \left[z \right]=2 and \left\{x \right\}=0.0 similarly sub (3) from (4) we get \left[y \right]+\left\{x \right\}=0.3 or \left[y \right]=0 and \left\{x \right\}=0.3 so final value of x=\left[x \right]+\left\{x \right\}=4+0.3=4.3 y=\left[y\right]+\left\{y\right\}=0+0.2=0.2