P&C signs

Find the total no. of ways in which 6 "+" and 4 "-" signs can be arranged in a line such that no 2 -ve signs occur together.

Ans : ⁷C₄ = 35

Why is it not : 6! x ⁷P₄

4 Answers

I think so they considered each + to be different which is wrong

the answer is correct

no of ways to arrange 6 + signs in a row is 1... because all + signs are teh same

now you have to insert 4 - signs in 7 gaps...

hence ⁷C⁴

yes...right:)...,,,,,,abheek since + are all same and - are all same so

(6! x 7P4) /(6! x 4!) which is same as the answer

Thnx

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