[5]
pagal hun main...
to ye hoga naa...
1-(1/4*5/6+3/4*1/6)
if the prob of horse p winning a race is 1/ 4 and that of horse Q winning the race is 1/ 6 find the prob that none will win
arrey yaar kya kar raha hai
can two horses win together?
these are not independent but exclusive events!!
kaise priyam..
they are all exclusive
let there be n horses
probabilty of A winning is P(A), B is P(B) and so on
then
P(A)+P(B)+P(C)+....P(X)=1
Hence
P(C)+....P(X)=1 - P(A) - P(B)
Which is the probabilty of A and B not winning...