i did this type once on FORUM.........
IT WAS SURBHI's dbt.......
sum of numbers of using digits 1 2 3 4
and also find the same for 2 0 3 1
and 2 2 0 1
i actually wanna know the concept how we proceed .....
number of times 1 comes in the first digit is given by 3!=6
same for 2, 3, 4
hence
sum of all the first digits is
6(1+2+3+4) x 103
similarly for other digits (units tens and hundreds)
hence the answer will be
6(1+2+3+4)(1+10+100+1000)
= 66660
zero wala case has to handled differently..
there you will not have equal in all cases.. try that one too :)
there the only thing is that zero cannot be the first digit..
give it a shot
i did this type once on FORUM.........
IT WAS SURBHI's dbt.......