1057is the answer 180?
Soumyabrata Mondal kaise kiya???Upvote·0· Reply ·2013-02-21 23:39:03
Akshay Ginodia answer is 26250 and whoever does it plz give the soln. ...i don't know how to solve it
6 apples and 6 mangoes are to be distributed among 10 boys so that each boy gets atleast 1 fruit.Find the number of ways in which the fruits can be distributed.
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4 Answers
10571057first make sure each boy gets a fruit.3 cases:
1)6 Mangoes,4 Apples.The rest 2 apples can be given in 10C2 ways.
2)4 Mangoes,6 Apples.The rest 2 mangoes can be given in 10C2 ways.
3)5 Mangoes,5 Apples.The rest 2 fruits(1 apple and 1 mango)can be given in 2x10C2 ways.
Total ways=4x10C2 ways=180.
1057are all the 6 mangoes different? :P
- Akshay Ginodia heheh..no :P
Hardik Sheth mangoes r the same but boys are different.hence you r missing out on a lot of combinations by just assigning (6+4)(4+6)(5+5)..
333there are two cases-
CASE 1:
one boy takes three apples others get one each.
CASE 2:
two boys take two each and rest take one.
Case 1
we have to select the guy taking 3,which can be done in 10C2 ways.
part 1-all apples---remaining fruits (3 apples + 6 mangoes) among nine in 9C6 ways.
part 2-all mangoes---remaining fruits (6 apples + 3 mangoes) among nine in 9C6 ways.
part 3-2 apples 1 mango---remaining fruits (4 apples + 5 mangoes) among nine in 9C5 ways.
part 4-1 apples 2 mango---remaining fruits (5 apples + 4 mangoes) among nine in 9C5 ways.
for case 1-10(84+84+136+136)=4400.
now someone do case 2!!
- Hardik Sheth 10 c 1 ways..not 10 c 2
- Akshay Ginodia ya thats what i had done but somehow the answer is not coming out to be right
- Hardik Sheth there will be 9 cases for the 2 boys one...3*3 as aa,am,mm are possibilities for the boys wher a is for apple and...