permutation combination

out of 8 sailors on a boat, 3 can work only on one particular side and 2 only on the other side. in how many ways can the sailors be arranged on the boat ????

14 Answers

1
Philip Calvert ·

well tell something about the rest three also

1
big looser ......... ·

i have posted complete question

13
Двҥїяuρ now in medical c ·

should there be 4 sailors on each sides?

1
Philip Calvert ·

arre so the rest three stay where?
are they with any of these groups
or they have a separate group ?
whether they can be on the forecastle or the after deck
or where?
what is the size of the boat?
kuch to batao how many assumptions can we take

1
Philip Calvert ·

is the answer 2*(3!*2!*8)

1
big looser ......... ·

yaar buk mein ye pura question dia hai , main apne aap se condition nai bna sakta dude.... ho sakta hai ki question wrong ho

1
Philip Calvert ·

check the answer now is it anywhere close ? it can be 96 or 2 * 96 otherwise we have to understand the question clearly

13
Двҥїяuρ now in medical c ·

i think we should take 4 sailors each side.....

1
Philip Calvert ·

ek taraf jyada hone se now doob jayegi toh nao banane wale ko khud chullu bhar paani mein doob jana chahiye

1
Philip Calvert ·

aman tell answer so that we can check

1
big looser ......... ·

1728

11
virang1 Jhaveri ·

The ans:-

The special three can be arranged in 4 places on one side There are 4!ways

Now the two on the other side also have 4 places . Therefore 4!/2!ways

Now there are 3 places remaining and 3 sailors therefore 3! ways

Therefore the total ways are:-
4!*4!/2!*3!
4*3*2*4*3*3*2*1
12*8*9*2
=12*72*2
=12*144
=1728

1
mkagenius ·

naw mat dubao yaar....

rest 3 ko 1-1 kar ke both sides rakh ke p and c kar do...

13
Двҥїяuρ now in medical c ·

Take 3 sailors working on one side and 2 on other side
So there are 2 places left on one side where 2 of 3 others can sit.
L1 R1
L2 R2
* R3
* *

so required no. of cases: 3C2*4!*4!=1728

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