Permutations-(AKS)

JEE Mains 2015 Coaching › Algebra questions › Permutations-(AKS)

A 15-letter word is to be formed by using 5A's, 5B's and 5C's.....Such dat there are no A's in the 1st 5 places, no B's in the next 5 places and no C's in the last 5 places. How many such words are possible?

AKS solved dis for me - but I failed to get the soln at home...[2]

#Mathematics #Algebra

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Ankur Jay ·2010-01-05 09:40:28

Well dude, the first answer i would give is 0. Cuz there is no sensible word that can be formed from that group of letters [3].

However, if you are asking the permutations possible according to the conditions you posted ,there are only 2 ways.

BBBBB CCCCC AAAAA and CCCCC AAAAA BBBBB

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Maths Musing ·2010-01-05 10:31:03

erm--- this can also be a part --- cccbb aaacc bbbaa

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Devil ·2010-01-06 01:08:33

Nope Ankur [3] [4]

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Devil ·2010-01-16 09:25:12

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eureka123 ·2010-01-21 09:18:03

short on time...so copy paste.....

dont curse me plzz.[2]

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Basic Integral Calculus Operators Symbols Matrix Cases

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° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω

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Permutations-(AKS)

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