phys in maths

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a particle has 2 velocities of eqaul magnitude inclined to ecah othr at an angle @ if one of them is halved the angle betwn d othr and the original resultant velocity is bisected by d new resulatnt then @ is

???

#Mathematics #Algebra

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6 Answers

9

Celestine preetham ·2009-04-22 00:18:06

v = 2vcos@/2

so @ is 120

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Rohan Ghosh ·2009-04-22 04:28:36

cudnt get the problem clearly ..

finally after one of the velocities is halved we get

tan(Î±/4)=(vsin(Î±/2)/2)/(vcosÎ±+v/2cosÎ±)

thus

tan(Î±/4)=tan(Î±/2)/3

substitute

tan(Î±/2)=2tan(Î±/4)/(1-tan²(Î±/4)

ou will get

tanÎ±/4=1/âˆš3

thus Î±/4=30 and Î±=120

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Rohan Ghosh ·2009-04-25 03:46:03

cudnt get your message ~~~~~ ..

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Rohan Ghosh ·2009-04-25 03:46:30

if it isnt clear shall i post a figure??

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Â°áƒ¦â€¢à¹“ÑÏ…Î ·2009-04-25 03:48:13

ya d thing is at that tym meko woh formula ni pata tha

nw i noe so thanks

bt it wud b definately helpful if u post ur fig i mean d diagrm...lolz or u'll post ur fig ;)

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Rohan Ghosh ·2009-04-25 03:57:44

the dotted lines represent the x and y components after the transformation

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