let the digits be x(unit), x+d(tens) and x+2d (hundreds)
also x,x+d and x+2d+4 are in GP
so (x+d)2=x(x+2d+4)
d2=4x
which is true only for x=1 and d=2
so the number is 531
Find a 3 digit number whose digits are in A.P. and if 400 is added to it, then its digits are in G.P.
let the digits be x(unit), x+d(tens) and x+2d (hundreds)
also x,x+d and x+2d+4 are in GP
so (x+d)2=x(x+2d+4)
d2=4x
which is true only for x=1 and d=2
so the number is 531
it will be a little better if we take the three digits as (x+d), x and (x-d).....