what about one eureka is it correct?
exercise 13.4
q3) let x represent difference b/w no. of heads and no. of tails obtained when a coin is tossed 6 times.what are possible values of x?
q12 ) 2 numbers are selceted at random from first 6 positive integers without replacement.let x denote larger of 2 nos. obtained.find E(x)
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UP 0 DOWN 0 0 10
10 Answers
no i thought th e same too but ans is 0,2,4,6[2][2]........plzzzzzzz help
u r rite eureka
the answer for first is
0,2,4,6
H T DIff
6 0 6
5 1 4
4 2 2
3 3 0
and vice versa which will have same values
shit man...........i dont know what i am doing today...............[2][2][2]
plz check out first question.......plzzzzzzzzzzzzzzzzzzz
hey yaar 2nd one is simple eureka.......
X:Larger of the Two=2,3,4,5,6
P(X==2)=1/6C2=1/15
P(X==3)=2/1/6C2=2/15
P(X==4)=3/1/6C2=3/15
P(X==5)=4/1/6C2=4/15
P(X==6)=5/1/6C2=5/15
X : 2 3 4 5 6
P(X) : 1/15 2/15 3/15 4/15 5/15..........
Eureka Now.........Mean can be found out.........
Mean==2*1/15+3*2/15+4*3/15+5*4/15+6*5/15
==2/15+6/15+12/15+20/15+30/15
==2+6+12+20+30/15
==70/15
==14/3
Got it Eureka........
yaar ye wala step expalin karo..........bold vala......
P(X==4)=3/1/6C2=3/15