first case:SUCES...
no of ways in which two S's arent together is 5!2-4!=36
second case:SUCCE
no of ways in which two C's arent together is 5!2-4!=36
3rd case:SSCC(E/U)
let us consider SSCC as one letter...the only ways in which the two S's and C's arent together is SCSC or CSCS...
now (SCSC) is a letter and (E/U) is a letter...they can be arranged in 2! ways....E or U can be chosen in 2 ways and SCSC can be arranged in 2 ways...
so total 8 ways...
4th case: SSS(2 out of C,U,E)
S_S_S...
only the above arrangement is possible....so 2x3C2 ways...
so total is 36+36+8+6=86 ways....