prob

A number is seelceted randomly from 3 digit nos. 100,101...........999 .The prob that in the selected no. at least one of the digits is 9 is??

12 Answers

24
eureka123 ·

is ther any other method than direct counting??

62
Lokesh Verma ·

1- p that none is 9

prob 1st digit is not 9 =8/9
prob 2nd digit is not 9 is 9/10
prob 3rd digit is not 9 is 9/10

total prob = 1-8/9 x 9/10 x 9/10 =1-72/100 = 28/100!

24
eureka123 ·

options are
6/15
1/3
<1/3
<3/4

62
Lokesh Verma ·

<1/3 :)

13
Двҥїяuρ now in medical c ·

1 - {(8*9*9)/(9*10*10)}

7/25

13
Двҥїяuρ now in medical c ·

sorry bhaiya...din see ur post...

62
Lokesh Verma ·

it is ok :)

24
eureka123 ·

no sir i also got the same.....but it is worng..

62
Lokesh Verma ·

what is the source of the question?

13
Двҥїяuρ now in medical c ·

[11]

11
rkrish ·

[ (1/9)*(9/10)*(9/10) + (8/9)*(1/10)*(9/10) + (8/9)*(9/10)*(1/10) + (1/9)*(1/10)*(9/10) + (8/9)*(1/10)*(1/10) + (1/9)*(9/10)*(1/10) + (1/9)*(1/10)*(1/10) ] = (9(9+8+8+1+1) + 8+1)/900 = 252/900 = 28/100 = 7/25 (same ans. as above!!)

7/25 < 6/15
7/25 < 1/3
7/25 < 1/3
7/25 < 3/4

62
Lokesh Verma ·

yup.. i guess we should close this one now :)

Your Answer

Close [X]