prob3

a bag contains 5 white and 9 black balls 3 balls are drawn twice . balls are replaced before the second draw. what is the prob that in the first draw 3 white and in second draw 3 lack balls will be drawn

3 Answers

33
Abhishek Priyam ·

5C3*9C3/14C3*14C3

1
spiderman ·

priyam yaar please explain method ........

62
Lokesh Verma ·

No fo ways to draw 3 white balls is

4C3

No of ways to draw 4 black balls is 9C3

NUmerator inPriyam's solution gives the product.. (Possible cases)

14C3 is the no of ways to draw 3balls.

Denominator gives the no of ways to draw 3 balls twice.

Hence the answer

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