probability 2

2)a natural no x ischossen at random frm dfirst 100 natural nos . d prob that x+100/x>50 is ?
( here if we take ne no gr8tr then 50 then it satisfies d given condition in addition to this if we take 1,2,48,49 it safisties it so ac 2 me d ansewr shud b sumwhat 54/100) bt thats wrng acc to d buk

7 Answers

62
Lokesh Verma ·

yeah it is wrong..

i think this is right!
try taking this

x/10+10/x>5

this might help!!!

62
Lokesh Verma ·

arrey is this 54 or 55 .. see carefully !

1
Rohan Ghosh ·

solving the inequality
we get
x<25-5√21 or x>25+5√21
we get x=1,2 and x=48,49..100

so total possible values of x=

1,2,48,49..100

no of value possible = 51+4=55

hence probability =55/100

1
°ღ•๓яυΠ·

answer given is 1/20

1
Rohan Ghosh ·

the answer given is not possible as then they mean to say only 5 possible values of x!!
then i think all possible natural numbers must be chosen from the first 50 and not the first 100

1
°ღ•๓яυΠ·

may b really that's frm tmh .....that buk hardly goes wrng so .....guessd m wrng ............neways thanks

62
Lokesh Verma ·

that is why i said in my first post.. we have to be careful aobut the definiton.. there are a lot of them...

:)

but i think this is not a question worth wasting more time.. i think we have enuf idea to do what has to be done..

IIT will not give vague questions :)

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