Probability

For the three events A, B and C. P (exactly one of events A or B occurs) = P (exactly one of events B or C occurs) = P (exactly one of events C or A occurs) = p and P (all events occur simultaneously) = p2, where 0 < p < 1/2. Then the probability of atleast one of the three events A, B and C occurring is

1) (3p + 2p^2)/2

2) (p + 3p^2)/3

3) (p + 3p^2)/4

4) (3p + 2p^2)

2 Answers

11
sagnik sarkar ·

Pls solve...

262
Aditya Bhutra ·

getting (1) using the formula for p(AUBUC)

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