11@gordo
for a.p. probability:
P(required) = (18+8+5+3+2+2+1+1+1)/(20c3)
ans= 41/190
Three numbers are chosen at random from 1 to 20. The probability that they are consecutive is
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47 Answers
1try solving for the numbers to be in a.p
revised question: probability of the 3 numbers being in ap.
nice one.
11
11try these :
LEVEL I:
Q1. 10 NO'S ARE CHOSEN FROM AMONG THE NO'S 1-100 AND ARRANGED IN INCREASING ORDER . FIND THE PROBABILITY THAT 45 IS THE 5TH NO FROM LEFT IN THIS ORDER (REMEMBER THE ARRANGEMENT IS DONE IN INCREASING ORDER).
LEVEL II:
Q2. A WIRE OF LENGTH L IS CUT INTO THREE PIECES . FIND PROBABILITY THAT THESE PIECES FORM A TRIANGLE
LEVEL III: (NOT REALLY A LEVEL III QUESTION ...DEPENDS ON YOUR COMMON SENSE)
Q3. TWO CARDS ARE DRAWN FROM A PACK OF CARDS (A 52 CARD DECK).FIND PROBABILITY THAT ONE CARD IS HEART AND OTHER IS ACE.
1for A.P probability question:
P(required)=(18+16+14+12+10+8+6+4+2)/(20C3)
=90/20c3
1Level 3 ans:
probability of getting a heart or an ace=(13+3)/52=16/52=4/13
11there some mistake in a.p. answer i gave the correct answer would be:
P(required)=(18+16+10+6+4+4+2+2+2)/(20c3)
= 64/190
=32/95
11@ronak
ur level one question's answer maybe right( i dont know the answer)
but ur level 3 question's answer is wrong
