1
ankit mahapatra
·2009-03-12 07:57:35
7? Is that the sum of pair of dices?
13
ДвҥїÑuÏ now in medical c
·2009-03-13 04:57:37
7 cards are drawn at random from a pack of 52 cards what is probability that 3 red 4 black P(A)=\frac{26}{52}\frac{25}{51}\frac{24}{50}\frac{26}{49}\frac{25}{48}\frac{24}{47}\frac{23}{46}=\frac{325}{39151}
62
Lokesh Verma
·2009-03-13 05:15:16
spider..
you have to multiply the answer you are geting by 7! also..
You have just chosen them..
I think you have not taken the order into consideration.
13
ДвҥїÑuÏ now in medical c
·2009-03-13 05:20:00
A and B throw alternatevely with a pair of dice . A wins if he throws 6 before B throws 7 and B wins if he throws 7 before A 6 find the chances of winning if A makes the first throw
Probability of winning of A=5/36+31/36*5/6*5/36+31/36*5/6*31/36*5/6*5/36+.........∞
1
spiderman
·2009-03-13 06:52:07
sir multiply by 7 factorial?? 52C7 ke alaawa? [7]
62
Lokesh Verma
·2009-03-13 07:02:56
A wins if he throws 6 before B throws 7 and B wins if he throws 7 before A 6 find the chances of winning if A makes the first throw
Another way by reccursion.. see if you understand
p- probability that A throws 6 = 5/36
q - probabilty that B throws 7 = 6/36
P(A)= p+(1-p)(1-q)P(A)
P(A)= 5/36+31x5/216P(A)
P(A)= 5/36+155/216P(A)
61/216 P(A)= 5/36
P(A)= 30/61
P(B)=31/61
IS this proof obvious? And have i made any calculation mistakes.. pls check